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Ex 5.3, 6 - Solve x2 - x + 2 = 0 - Class 11 CBSE - Quadaratic equation

Ex 5.3, 6 - Chapter 5 Class 11 Complex Numbers - Part 2

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Ex5.3, 6 Solve the equation π‘₯2 – π‘₯ + 2 = 0 x2 – x + 2 = 0 The above equation is of the form π‘Žπ‘₯2 + 𝑏π‘₯ + 𝑐 = 0 Where a = 1 , b = –1 , c = 2 x = (βˆ’π‘ Β± √( 𝑏^2 βˆ’4π‘Žπ‘ ))/2π‘Ž x = (βˆ’(βˆ’1) Β± √((βˆ’1)^2 βˆ’ 4 Γ— 1 Γ— 2))/(2 Γ— 1) = (1 Β± √(1βˆ’8))/2 = (1 Β± √(βˆ’7))/2 = (1 Β± √(βˆ’1 Γ— 7))/2 = (1Β± √(βˆ’1) Γ—βˆš7)/2 = (1 Β± √7 𝑖)/2 Thus, π‘₯ = (1 Β± √7 𝑖)/2

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