

Ex 5.3
Last updated at Sept. 3, 2021 by Teachoo
Ex5.3, 6 Solve the equation π₯2 β π₯ + 2 = 0 x2 β x + 2 = 0 The above equation is of the form ππ₯2 + ππ₯ + π = 0 Where a = 1 , b = β1 , c = 2 x = (βπ Β± β( π^2 β4ππ ))/2π x = (β(β1) Β± β((β1)^2 β 4 Γ 1 Γ 2))/(2 Γ 1) = (1 Β± β(1β8))/2 = (1 Β± β(β7))/2 = (1 Β± β(β1 Γ 7))/2 = (1Β± β(β1) Γβ7)/2 = (1 Β± β7 π)/2 Thus, π₯ = (1 Β± β7 π)/2