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Ex 5.3, 4 - Solve -x2 + x - 2 = 0 - Class 11 Complex - Quadaratic equation

Ex 5.3, 4 - Chapter 5 Class 11 Complex Numbers - Part 2

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Ex5.3, 4 Solve the equation –π‘₯2 + π‘₯ – 2 = 0 –π‘₯2 + π‘₯ – 2 = 0 The above equation is of the form π‘Žπ‘₯2 + 𝑏π‘₯ + 𝑐 = 0 Where a = –1, b = 1, and c = –2 π‘₯ = (βˆ’π‘ Β± √( 𝑏^2 βˆ’ 4π‘Žπ‘ ))/2π‘Ž π‘₯ = (βˆ’1 Β± √((1)^2 βˆ’ 4 Γ— (βˆ’1) (βˆ’2)))/(2 Γ— "(βˆ’" 1)) = (βˆ’1Β± √(1 βˆ’ 4 Γ— (+2)))/("βˆ’" 2) = (1 Β± √(1 βˆ’ 8))/(βˆ’2) = (βˆ’ 1 Β± √(βˆ’ 7))/(βˆ’2) = (βˆ’ 1 Β± √( 7 Γ—βˆ’1))/(βˆ’2) = (βˆ’1 Β± √7 𝑖)/(βˆ’ 2) = (βˆ’(βˆ’1 Β± √7 𝑖))/( 2) = (1 βˆ“ √7 𝑖)/2 Thus, π‘₯ = (1 βˆ“ √7 𝑖)/2

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