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Ex 3.2, 9 - Find value of sin -11pi/3 - Chapter 3 Class 11 - Teachoo

Ex 3.2, 9 - Chapter 3 Class 11 Trigonometric Functions - Part 2

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Ex 3.2,9 Find the value of the trigonometric function sin (–11"Ο€" /3) sin ((βˆ’11 πœ‹)/3) = –sin ((11 πœ‹)/3) = –sin ("3 " 2/3 " Ο€" ) = –sin ("4Ο€ – " 1/3 " Ο€" ) = –sin ((βˆ’1)/3 " Ο€" ) Values of sin x repeats after an interval of 2Ο€ , Hence ignoring 4Ο€ i.e. 2 Γ— (2Ο€) Rough So, 11/3 = 3 2/3 = 3 + 2/3 or 4 – 1/3 We take 4 – 1/3 as it is even = – ("–sin " (1/3 " Ο€" )) = sin (1/3 " Ο€" ) = sin 60Β° = βˆšπŸ‘/𝟐 ( As sin(βˆ’x) = βˆ’sin x )

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.