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Ex 3.2, 9 - Find value of sin -11pi/3 - Chapter 3 Class 11 - Teachoo

Ex 3.2, 9 - Chapter 3 Class 11 Trigonometric Functions - Part 2

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Ex 3.2,9 Find the value of the trigonometric function sin (–11"π" /3) sin ((−11 𝜋)/3) = –sin ((11 𝜋)/3) = –sin ("3 " 2/3 " π" ) = –sin ("4π – " 1/3 " π" ) = –sin ((−1)/3 " π" ) Values of sin x repeats after an interval of 2π , Hence ignoring 4π i.e. 2 × (2π) Rough So, 11/3 = 3 2/3 = 3 + 2/3 or 4 – 1/3 We take 4 – 1/3 as it is even = – ("–sin " (1/3 " π" )) = sin (1/3 " π" ) = sin 60° = √𝟑/𝟐 ( As sin(−x) = −sin x )

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.