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Ex 3.2, 9 - Chapter 3 Class 11 Trigonometric Functions
Last updated at June 22, 2023 by Teachoo
Chapter 3 Class 11 Trigonometric Functions
Serial order wise
Transcript
Ex 3.2,9 Find the value of the trigonometric function sin (β11"Ο" /3) sin ((βππ π )/π) = βsin ((11 π)/3) = βsin ("3 " π/π " Ο" ) = βsin ("4Ο β " π/π " Ο" ) = βsin ((βπ)/π " Ο" ) Rough So, 11/3 = 3 2/3 = 3 + 2/3 or 4 β 1/3 We take 4 β π/π as it is even = β ("βsin " (1/3 " Ο" )) = sin (π/π " Ο" ) = sin 60Β° = βπ/π
