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Last updated at Feb. 12, 2020 by Teachoo
Transcript
Ex 3.2,9 Find the value of the trigonometric function sin (β11"Ο" /3) sin ((β11 π)/3) = βsin ((11 π)/3) = βsin ("3 " 2/3 " Ο" ) = βsin ("4Ο β " 1/3 " Ο" ) = βsin ((β1)/3 " Ο" ) Values of sin x repeats after an interval of 2Ο , Hence ignoring 4Ο i.e. 2 Γ (2Ο) Rough So, 11/3 = 3 2/3 = 3 + 2/3 or 4 β 1/3 We take 4 β 1/3 as it is even = β ("βsin " (1/3 " Ο" )) = sin (1/3 " Ο" ) = sin 60Β° = βπ/π ( As sin(βx) = βsin x )
Ex 3.2
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