Chapter 3 Class 11 Trigonometric Functions

Serial order wise

Last updated at April 16, 2024 by Teachoo

Ex 3.2, 5 Find the values of other five trigonometric functions if tanβ‘π₯ = β5/12 , π₯ lies in second quadrant. Since x lies in llnd Quadrant So, sin x will be positive But tan x and cos x will be negative We know that 1 + tan2x = sec2x 1 + ((β5)/12)^2 = sec2x 1 + 25/144 = sec2x (144 + 25)/144 = sec2x 169/144 = sec2x sec2x = 169/144 sec2x = πππ/πππ sec x = Β± β(169/144) sec x = Β± ππ/ππ As x is in llnd Quadrant, cos x is negative in IInd quadrant So, sec x is negative in llnd Quadrant β΄ sec x = (βππ)/ππ cos x = 1/sππβ‘π₯ = 1/((β13)/12) = (βππ)/ππ tan x = sinβ‘π₯/cosβ‘π₯ tan x Γ cos x = sin x sin x = tan x Γ cos x = (β5)/12 Γ (β12)/13 = π/ππ cosec x = 1/π ππβ‘π₯ = 1/(5/13) = ππ/π cot x = 1/(π‘ππ π₯) = 1/((β5)/12) = (βππ)/π