Ex 3.2

Chapter 3 Class 11 Trigonometric Functions
Serial order wise

### Transcript

Ex 3.2, 5 Find the values of other five trigonometric functions if tanβ‘π₯ = β5/12 , π₯ lies in second quadrant. Since x lies in llnd Quadrant So, sin x will be positive But tan x and cos x will be negative We know that 1 + tan2x = sec2x 1 + ((β5)/12)^2 = sec2x 1 + 25/144 = sec2x (144 + 25)/144 = sec2x 169/144 = sec2x sec2x = 169/144 sec2x = πππ/πππ sec x = Β± β(169/144) sec x = Β± ππ/ππ As x is in llnd Quadrant, cos x is negative in IInd quadrant So, sec x is negative in llnd Quadrant β΄ sec x = (βππ)/ππ cos x = 1/sππβ‘π₯ = 1/((β13)/12) = (βππ)/ππ tan x = sinβ‘π₯/cosβ‘π₯ tan x Γ cos x = sin x sin x = tan x Γ cos x = (β5)/12 Γ (β12)/13 = π/ππ cosec x = 1/π ππβ‘π₯ = 1/(5/13) = ππ/π cot x = 1/(π‘ππ π₯) = 1/((β5)/12) = (βππ)/π

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#### Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.