


Introducing your new favourite teacher - Teachoo Black, at only βΉ83 per month
Finding Value of trignometric functions, given other functions
Finding Value of trignometric functions, given other functions
Last updated at Sept. 3, 2021 by Teachoo
Ex 3.2, 4 Find the values of other five trigonometric functions if sec x = 13/5 , π₯ lies in fourth quadrant. Since x lies in the lVth Quadrant Where cos will be positive But sin and tan will be negative We know that 1 + tan2x = sec2x 1 + tan2x = (13/5)^2 tan2x = (13/5)^2β 1 tan2x = 169/25 β 1 tan2x = (169 β 25)/25 tan2x = 144/25 tan x = Β± β(144/25) tan x = Β± 12/5 Since x is in lVth Quadrant tan x is negative in lVth Quadrant β΄ tan x = (βππ)/π cot x = 1/tππβ‘π₯ = 1/(" " (β12)/5) = (βπ)/ππ tan x = sinβ‘π₯/cosβ‘π₯ sin x = (tan x) Γ (cos x ) = (β12)/5 Γ 5/13 = (βππ)/ππ cos x = 1/sππβ‘π₯ = 1/(" " 13/5) = π/ππ cosec x = 1/sinβ‘π₯ = (βππ)/ππ