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Ex 3.1, 5 - In a circle of diameter 40 cm, length of a chord - Ex 3.1

  1. Chapter 3 Class 11 Trigonometric Functions
  2. Serial order wise
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Ex3.1, 5 In a circle of diameter 40 cm, the length of a chord is 20 cm. Find the length of minor arc of the chord. Given Diameter = 40 cm So, Radius = r = 20 cm In figure, AB =r= 20 cm AC =r= 20 cm BC =Length of chord = 20 cm So,AB = AC = BC = 20 cm Hence Δ ABC is equilateral Hence ∠ BAC is 60° 𝜃 = 60° Hence θ = 60o = 60o × 𝜋/(180°) = 𝜋/3 Now Putting values in formula 𝑙 = r θ = 20 × (𝜋 )/3 = (20𝜋 )/3 Hence, length of minor arc of chord is (20𝜋 )/3

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