Chapter 14 Class 10 Statistics
Example 3 Important
Example 4 Important
Example 6 Important
Example 7 Important
Example 8 You are here
Question 1 Important Deleted for CBSE Board 2025 Exams
Ex 13.1, 3 Important
Ex 13.3, 4 Important
Ex 13.3, 6 Important
Question 1 Deleted for CBSE Board 2025 Exams
Question 2 Important Deleted for CBSE Board 2025 Exams
Question 3 Deleted for CBSE Board 2025 Exams
Chapter 14 Class 10 Statistics
Last updated at April 16, 2024 by Teachoo
Example 8 The median of the following data is 525. Find the values of x and y, if the total frequency is 100. Since Median = 525 500 – 600 is Median Class Now, Median = l + (𝑁/2 −𝑐𝑓)/𝑓 × h Where N = ∑▒𝑓𝑖 l = h = cf = f = Putting values in formula Median = l + (𝑁/2 −𝑐𝑓)/𝑓 × h 525 = 500 + (𝟏𝟎𝟎/𝟐 −(𝟑𝟔 + 𝒙))/𝟐𝟎 × 100 525 = 500 + (50 – (36 + x)) × 5 525 – 500 = (50 – 36 – x) × 5 25 = (14 – x) × 5 25 = 14(5) – 5x 25 = 70 – 5x 5x = 70 – 25 5x = 45 x = 45/5 x = 9 Also, ∑▒𝑓𝑖 = 76 + x + y 100 = 76 + x + y 100 – 76 = 9 + y 24 = 9 + y y = 24 – 9 y = 15