Chapter 14 Class 10 Statistics

Class 10
Important Questions for Exam - Class 10

### Transcript

Example 3 (Method 1 β Direct Method) The distribution below shows the number of wickets taken by bowlers in one-day cricket matches. Find the mean number of wickets by choosing a suitable method. What does the mean signify? Here Class Size is not same, So, we solve by Direct Method Mean(π₯ Μ) = (ββπππ₯π)/(ββππ) π₯ Μ = 6880/45 π₯ Μ = 152.89 Thus, Mean signifies that on average, 45 bowlers take 152.89 wickets Example 3 (Method 2 β Step Deviation Method) The distribution below shows the number of wickets taken by bowlers in one-day cricket matches. Find the mean number of wickets by choosing a suitable method. What does the mean signify? Here Class Size is not sameβ¦ So, in Step Deviation Method Mean(π₯ Μ) = a + h Γ (ββππππ)/(ββππ) We use a value of h which can divide ππ = π₯π β a Mean(π₯ Μ) = a + h Γ (ββππππ)/(ββππ) Where a = Assumed Mean Let h = Class interval Also, ββππ = 45 ββππππ = β212 Putting values in formula Mean(π Μ) = a + h Γ (ββππππ)/(ββππ) π₯ Μ = 200 + 10 Γ (β212)/45 π₯ Μ = 200 β 47.11 π Μ = 152.89 Thus, Mean signifies that on average, 45 bowlers take 152.89 wickets