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Ex 13.2, 6 - A solid iron pole consists of a cylinder of height - Ex 13.2

Ex 13.2, 6 - Chapter 13 Class 10 Surface Areas and Volumes - Part 2
Ex 13.2, 6 - Chapter 13 Class 10 Surface Areas and Volumes - Part 3


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Ex 13.2, 6 A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm, which is surmounted by another cylinder of height 60 cm and radius 8 cm. Find the mass of the pole, given that 1 cm3 of iron has approximately 8g mass. (Use π = 3.14) To find mass of pole, we need to find volume of pole Volume of pole = volume of small cylinder + volume of large cylinder Volume of small cylinder Radius = r = 8 cm Height = h = 60 cm Volume of small cylinder = 𝜋𝑟2ℎ = 3.14×(8)2×(60) = 3.14×64×60 = 12057.6 cm2 Volume of large cylinder Height = h = 220 cm Radius = r = Diameter/2 = 24/2 = 12 cm Volume of large cylinder = 𝜋𝑟2ℎ = 3.14×(12)2×220 = 3.14×144×220 = 99475.2 cm3 Now, Volume of pole = Volume of small cylinder + Volume of large cylinder = 12057. 6 + 99475.2 = 111532.8 cm3 Given that, 1 cm3 of iron has 8 g mass. So, 1 cm3 of iron has mass = 8 g So, 111532.8 cm3 cm3 of iron has mass = 111532.8 × 8 g = 892262.4 g = 892262.4/1000 kg = 892.2624 kg = 892.26 kg

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.