Ex 11.1, 2 - Chapter 11 Class 10 Areas related to Circles

Last updated at August 17, 2026 by

Ex 11.1, 2 - Find area of a quadrant whose circumference is 22 - Ex 11.1

part 2 - Ex 11.1, 2 - Ex 11.1 - Serial order wise - Chapter 11 Class 10 Areas related to Circles
part 3 - Ex 11.1, 2 - Ex 11.1 - Serial order wise - Chapter 11 Class 10 Areas related to Circles

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Transcript

Ex 11.1, 2 Find the area of a quadrant of a circle whose circumference is 22 cm. Area of quadrant = 1/4× Area of circle = 𝟏/𝟒 × 𝜋r2 Now, we need to find r. It is given that Circumference = 2πr 22 = 2πr 22/2 = πr 11 = πr 11/𝜋 = r r = 𝟏𝟏/𝝅 r = 11/(22/7) r = 11 × 7/22 r = 𝟕/𝟐 cm Now, Area of quadrant = 1/4× Area of circle = 1/4 × 𝜋r2 = 𝟏/𝟒×𝟐𝟐/𝟕×(𝟕/𝟐)^𝟐 = 1/4×22/7×(7 × 7)/(2 × 2) = 1/2×11/1×7/4 = 77/8 cm2

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