Check sibling questions

Ex 12.2, 2 - Find area of a quadrant whose circumference is 22 - Ex 12.2

Ex 12.2, 2 - Chapter 12 Class 10 Areas related to Circles - Part 2

This video is only available for Teachoo black users

Solve all your doubts with Teachoo Black (new monthly pack available now!)


Transcript

Ex 12.2, 2 Find the area of a quadrant of a circle whose circumference is 22 cm. Area of quadrant = 1/4 area of circle = 1/4 (" "r2 ) Now, we need to find r. It is given that Circumference = 2 r 22 = 2 r 22/2 = r 11 = r 11/ = r r = 11/ r = 11/(22/7) r = 11 7/22 r = 7/2 cm Now, area of quadrant = 1/4 area of circle = 1/4(" "r2) = 1/4 22/7 (7/2)^2 = 1/4 22/7 (7 7)/(2 2) = 1/2 11/1 7/4 = 77/8 cm2

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.