Ex 11.1, 2
Find the area of a quadrant of a circle whose circumference is 22 cm.
Area of quadrant = 1/4× Area of circle
= 𝟏/𝟒 × 𝜋r2
Now, we need to find r.
It is given that
Circumference = 2πr
22 = 2πr
22/2 = πr
11 = πr
11/𝜋 = r
r = 𝟏𝟏/𝝅
r = 11/(22/7)
r = 11 × 7/22
r = 𝟕/𝟐 cm
Now,
Area of quadrant = 1/4× Area of circle
= 1/4 × 𝜋r2
= 𝟏/𝟒×𝟐𝟐/𝟕×(𝟕/𝟐)^𝟐
= 1/4×22/7×(7 × 7)/(2 × 2)
= 1/2×11/1×7/4
= 77/8 cm2

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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