Ex 11.1, 2 - Chapter 11 Class 10 Areas related to Circles

Last updated at August 14, 2026 by

Ex 11.1, 2 - Find area of a quadrant whose circumference is 22 - Ex 11.1

part 2 - Ex 11.1, 2 - Ex 11.1 - Serial order wise - Chapter 11 Class 10 Areas related to Circles
part 3 - Ex 11.1, 2 - Ex 11.1 - Serial order wise - Chapter 11 Class 10 Areas related to Circles

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Transcript

Ex 11.1, 2 Find the area of a quadrant of a circle whose circumference is 22 cm. Area of quadrant = 1/4ร— Area of circle = ๐Ÿ/๐Ÿ’ ร— ๐œ‹r2 Now, we need to find r. It is given that Circumference = 2ฯ€r 22 = 2ฯ€r 22/2 = ฯ€r 11 = ฯ€r 11/๐œ‹ = r r = ๐Ÿ๐Ÿ/๐… r = 11/(22/7) r = 11 ร— 7/22 r = ๐Ÿ•/๐Ÿ cm Now, Area of quadrant = 1/4ร— Area of circle = 1/4 ร— ๐œ‹r2 = ๐Ÿ/๐Ÿ’ร—๐Ÿ๐Ÿ/๐Ÿ•ร—(๐Ÿ•/๐Ÿ)^๐Ÿ = 1/4ร—22/7ร—(7 ร— 7)/(2 ร— 2) = 1/2ร—11/1ร—7/4 = 77/8 cm2

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