Learn all Concepts of Chapter 5 Class 10 (with VIDEOS). Check - Arithmetic Progressions - Class 10

Last updated at May 29, 2018 by Teachoo
Transcript
Example 7 How many two-digit numbers are divisible by 3? Numbers divisible by 3 are 3, 6, 9, 12, …………….. Lowest two digit number divisible by 3 is 12 Highest two digit number divisible by 3 We know that 99/3 = 33 ∴ Highest two digit number divisible by 3 is 99 So the series starts with 12 and ends with 99. Difference between numbers is 3. So, the A.P. will be 12, 15, 18, 21, ………….99 We need to find n Last term of this series is 99 So, an = 99 & a = 12 d = 15 – 12 = 3 Now, an = a + (n – 1) d Putting values 99 = 12 + (n – 1) (3) 99 = 12 + 3n – 3 99 = 9 + 3n 3n = 99 – 9 3n = 90 n = 90/3 = 30 Therefore , there are 30 two digit numbers divisible by 3.
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