Example 5 - Chapter 5 Class 10 Arithmetic Progressions

Transcript

Example 5 Determine the AP whose 3rd term is 5 and the 7th term is 9. We know that an = a + (n 1)d From (1) & (2) 5 2d = 9 6d 6d 2d = 9 5 4d = 4 d = 4/4 d = 1 Putting d = 1 in (1) a = 5 2d a = 5 2(1) a = 5 2 a = 3 Hence , First term of an A.P = 3 Second term of AP = First term + common difference = 3 + 1 = 4 Third term of AP = Second term + common difference = 4 + 1 = 5 So the A.P is 3, 4, 5,