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Example 2 Important
Example 3
Example 4 Important
Example 5 You are here
Example 6 Important
Example 7
Example 8 Important
Example 9
Example 10
Example 11
Example 12
Example 13 Important
Example 14 (i)
Example 14 (ii)
Example 15 Important
Example 16 Important Deleted for CBSE Board 2022 Exams
Last updated at March 19, 2021 by Teachoo
Example 5 Determine the AP whose 3rd term is 5 and the 7th term is 9. We know that an = a + (n – 1)d From (1) & (2) 5 – 2d = 9 – 6d 6d – 2d = 9 – 5 Given 3rd term is 5 a3 = a + (3 – 1)d 5 = a + 2d a = 5 – 2d Given 7th term is 9 a7 = a + (7 – 1)d 9 = a + 6d a = 9 – 6d 4d = 4 d = 4/4 d = 1 Putting d = 1 in (1) a = 5 – 2d a = 5 – 2(1) a = 5 – 2 a = 3 Hence , First term of an A.P = 3 Second term of AP = First term + Common Difference = 3 + 1 = 4 Third term of AP = Second term + Common Difference = 4 + 1 = 5 So the A.P is 3, 4, 5, …………