Find the direction cosines of the following line: (3 − 𝑥)/(−1) = (2𝑦 − 1)/2 = 𝑧/4

This question is similar to Question 4 or 2nd CBSE Class 12 Sample Paper 2019 Boards 

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Transcript

Question 4 Find the direction cosines of the following line: (3 − 𝑥)/(−1) = (2𝑦 − 1)/2 = 𝑧/4 Given line (𝟑 − 𝒙)/(−𝟏) = (2𝑦 − 1)/2 = 𝑧/4 (−(𝑥 − 3) )/(−1) = (2𝑦 − 1)/2 = 𝑧/4 ((𝒙 − 𝟑) )/𝟏 = (2𝑦 − 1)/2 = 𝑧/4 ((𝑥 − 3) )/1 = 𝟐(𝒚 − ½)/𝟐 = 𝑧/4 ((𝑥 − 3) )/1 = ((𝒚 − ½))/𝟏 = 𝑧/4 So, direction ratios are 1, 1, 4 ½ marks ∴ a = 1, b = 1, c = 4 Direction cosines = 1/√(1^2 + 1^2 + 4^2 ) , 1/√(1^2 + 1^2 + 4^2 ) , 4/√(1^2 + 1^2 + 4^2 ) = 1/√(1 + 1 + 16) ,1/√(1 + 1 + 16) ,4/√(1 + 1 + 16) = 1/√18 ,1/√18 ,4/√18 = 1/√(2 × 9) ,1/√(2 × 9) ,4/√(2 × 9) = 𝟏/(𝟑√𝟐) , 𝟏/(𝟑√𝟐) , 𝟒/(𝟑√𝟐) ½ marks

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.