Find the direction cosines of the following line: (3 − š‘„)/(−1) = (2š‘¦ − 1)/2 = š‘§/4

This question is similar to Question 4 or 2nd CBSE Class 12 Sample Paper 2019 Boards 

Question 4 - CBSE Class 12 Sample Paper for 2022 Boards (For Term 2) - CBSE Class 12 Sample Paper for 2022 Boards (For Term 2)

part 2 - Question 4 - CBSE Class 12 Sample Paper for 2022 Boards (For Term 2) - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

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Question 4 Find the direction cosines of the following line: (3 āˆ’ š‘„)/(āˆ’1) = (2š‘¦ āˆ’ 1)/2 = š‘§/4 Given line (šŸ‘ āˆ’ š’™)/(āˆ’šŸ) = (2š‘¦ āˆ’ 1)/2 = š‘§/4 (āˆ’(š‘„ āˆ’ 3) )/(āˆ’1) = (2š‘¦ āˆ’ 1)/2 = š‘§/4 ((š’™ āˆ’ šŸ‘) )/šŸ = (2š‘¦ āˆ’ 1)/2 = š‘§/4 ((š‘„ āˆ’ 3) )/1 = šŸ(š’š āˆ’ ½)/šŸ = š‘§/4 ((š‘„ āˆ’ 3) )/1 = ((š’š āˆ’ ½))/šŸ = š‘§/4 So, direction ratios are 1, 1, 4 ½ marks ∓ a = 1, b = 1, c = 4 Direction cosines = 1/√(1^2 + 1^2 + 4^2 ) , 1/√(1^2 + 1^2 + 4^2 ) , 4/√(1^2 + 1^2 + 4^2 ) = 1/√(1 + 1 + 16) ,1/√(1 + 1 + 16) ,4/√(1 + 1 + 16) = 1/√18 ,1/√18 ,4/√18 = 1/√(2 Ɨ 9) ,1/√(2 Ɨ 9) ,4/√(2 Ɨ 9) = šŸ/(šŸ‘āˆššŸ) , šŸ/(šŸ‘āˆššŸ) , šŸ’/(šŸ‘āˆššŸ) ½ marks

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