Question 2 - Past Year MCQ - Chapter 7 Class 10 Coordinate Geometry

Last updated at Dec. 16, 2024 by

In fig 6.52, the area of ∆ ABC (in square units) is

(A) 15 

(B) 10

(C) 7.5 

(D) 2.5

This question is similar to Example 11 - Chapter 7 Class 10 Coordinate Geometry

In fig 6.52, the area of ∆ ABC (in square units) is - Class 10 [MCQ] - Past Year MCQ

part 2 - Question 2 - Past Year MCQ - Serial order wise - Chapter 7 Class 10 Coordinate Geometry

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Question 2 In fig 6.52, the area of ∆ ABC (in square units) is (A) 15 (B) 10 (C) 7.5 (D) 2.5 Vertices of triangle are A(1, 3), B(-1, 0) and C(4, 0) Here x1 = 1 , y1 = 3 x2 = −1 , y2 = 0 x3 = 4 , y3 = 0 Now, Area of triangle = 1/2 [ x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2) ] = 1/2 [ 1(0 – 0) + (−1)(0 – 3) + 4(3 – 0)] = 1/2 [ 1 × 0 + (−1) × (– 3) + 4 × 3 ] = 1/2 [ 0 + 3 + 12 ] = 1/2 × 15 = 7.5 square units So, the correct answer is (C)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo