Ex 4.4, 5 - Chapter 4 Class 10 Quadratic Equations (Term 2)

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Ex 4.4 ,5 Is it possible to design a rectangular park of perimeter 80 m and area 400 m2? If so, find its length and breadth. Let length be x Given that Perimeter = 80 m 2(Length + Breadth) = 80 m (Length + Breadth) = 80/2 (x + Breadth) = 40 Breadth = 40 – x Also, given that area = 400 m2 length × Breadth = 400 x (40 – x) = 400 40x – x2 = 400 40x – x2 – 400 = 0 0 = – 40x + x2 + 400 = 0 – 40x + x2 + 400 = 0 x2 – 40x + 400 = 0 We factorize by splitting the middle term x2 – 20x – 20x + 400 = 0 x (x – 20) – 20(x – 20) = 0 (x – 20) (x – 20) = 0 So, the roots of the equation are So, x = 20 is the solution ∴ Length = x = 20 m Breadth = 40 – x = 40 – 20 = 20 m