# Example 10

Last updated at June 29, 2018 by Teachoo

Last updated at June 29, 2018 by Teachoo

Transcript

Example 10 Let us consider the Example 3 of Section 3.2. Will the rails cross each other? The pair of linear equation formed were x + 2y – 4 = 0 2x + 4y – 12 = 0 From (1) x + 2y – 4 = 0 x = 4 – 2y Substitute the value of x in equation (2) 2x + 4y – 12 = 0 2 (4 – 2y) + 4y – 12 = 0 8 – 4y + 4y – 12 = 0 8 – 4y + 4y – 12 = 0 −4 = 0 Which is not correct Equation do not have a common solution . So , the two rails will not cross each other.

Example 6
Important

Example 10 Important You are here

Example 11 Important

Example 13 Important

Example 14 Important

Example 19 Important

Ex 3.2, 1 Important

Ex 3.2, 3 Important

Ex 3.2, 6 Important

Ex 3.2, 7 Important

Ex 3.5, 2 Important

Ex 3.6, 1 (i) and (ii) Important

Ex 3.6, 1 (iii) and (iv) Important

Ex 3.6, 1 (v) and (vi) Important

Ex 3.6, 1 (vii) and (viii) Important

Ex 3.6, 2 Important

Class 10

Important Questions for Exam - Class 10

- Chapter 1 Class 10 Real Numbers
- Chapter 2 Class 10 Polynomials
- Chapter 3 Class 10 Pair of Linear Equations in Two Variables
- Chapter 4 Class 10 Quadratic Equations
- Chapter 5 Class 10 Arithmetic Progressions
- Chapter 6 Class 10 Triangles
- Chapter 7 Class 10 Coordinate Geometry
- Chapter 8 Class 10 Introduction to Trignometry
- Chapter 9 Class 10 Some Applications of Trignometry
- Chapter 10 Class 10 Circles
- Chapter 11 Class 10 Constructions
- Chapter 12 Class 10 Areas related to Circles
- Chapter 13 Class 10 Surface Areas and Volumes
- Chapter 14 Class 10 Statistics
- Chapter 15 Class 10 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.