Check sibling questions

Ex 3.4, 2 (i) - If we add 1 to the numerator and subtract 1 from the

Ex 3.4, 2 (i) - Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Part 2
Ex 3.4, 2 (i) - Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Part 3 Ex 3.4, 2 (i) - Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Part 4

Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


Transcript

Ex 3.3, 2 Form the pair of linear equations in the following problems, and find their solutions (if they exist) by the elimination method : (i) If we add 1 to the numerator and subtract 1 from the denominator, a fraction reduces to 1. It becomes 1/2 if we only add 1 to the denominator. What is the fraction? Let Numerator be x and Denominator be y So, Fraction is 𝒙/π’š Given that, If 1 is added to numerator and 1 is subtracted from the denominator, fraction becomes 1. (π‘π‘’π‘›π‘’π‘Ÿπ‘Žπ‘‘π‘œπ‘Ÿ + 1)/(π·π‘’π‘›π‘œπ‘šπ‘–π‘›π‘Žπ‘‘π‘œπ‘Ÿ βˆ’1)= 1 (π‘₯ + 1)/(𝑦 βˆ’ 1)= 1 (x + 1) = (y – 1) x – y = –1 – 1 x – y = –2 Also, If we add 1 to the denominator, fraction becomes 1/2. π‘π‘’π‘šπ‘’π‘Ÿπ‘Žπ‘‘π‘œπ‘Ÿ/(π·π‘’π‘›π‘œπ‘šπ‘–π‘›π‘Žπ‘‘π‘œπ‘Ÿ + 1)=1/2 π‘₯/(𝑦 +1)=1/2 2x = y + 1 2x – y = 1 Hence, our equations are x – y = –2 …(1) 2x – y = 1 …(2) We use elimination method with equation (1) & (2) –x = –3 x = 3 Putting x = 3 in equation (1) x – y = –2 3 – y = –2 –y = –2 – 3 –y = –5 y = 5 So, x = 3, y = 5 is the solution of our equation ∴ Numerator = x = 3 & Denominator = y = 5 Hence, Original Fraction = π‘π‘’π‘šπ‘’π‘Ÿπ‘Žπ‘‘π‘œπ‘Ÿ/π·π‘’π‘›π‘œπ‘šπ‘–π‘›π‘Žπ‘‘π‘œπ‘Ÿ "= " π‘₯/𝑦=πŸ‘/πŸ“

Ask a doubt
Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.