Ex 3.3

Chapter 3 Class 10 Pair of Linear Equations in Two Variables
Serial order wise

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Transcript

Ex 3.3, 1 (Elimination) Solve the following pair of linear equations by the elimination method and the substitution method : (iv) π₯/2+2π¦/3=β1 πππ π₯βπ¦/3=3 Given x/2+2y/3=β1 (3(x) + 2(2y))/(2 Γ 3)=β1 (3π₯ + 4y)/6=β1 3x + 4y = β1 Γ 6 3x + 4y = β6 x β y/3=3 (3π₯ β π¦ )/3=3 3x β y = 3(3) 3x β y = 9 We use elimination method with equation (1) & (2) 5y = β 15 y=(β15)/( 5) y = β3 Putting y = β3 in equation (2) 3x β y = 9 3x β (β3) = 9 3x + 3 = 9 3x = 9 β 3 3x = 6 x = 6/3 x = 2 So, x = 2, y = β3 is the solution of the given equations Ex 3.3, 1 (Substitution) Solve the following pair of linear equations by the elimination method and the substitution method : (iv) π₯/2+2π¦/3=β1 πππ π₯βπ¦/3=3 Given x/2+2y/3=β1 (3(x) + 2(2y))/(2 Γ 3)=β1 (3π₯ + 4y)/6=β1 3x + 4y = β1 Γ 6 3x + 4y = β6 x β y/3=3 (3π₯ β π¦ )/3=3 3x β y = 3(3) 3x β y = 9 From (1) 3x + 4y = β6 3x = β6 β 4y Putting value of 3x in (2) 3x β y = 9 (β6 β 4y) β y = 9 β 4y β y = 9 + 6 β5y = 15 y = (β15)/( 5) y = β3 Putting y = β3 in equation (2) 3x β y = 9 3x β (β3) = 9 3x = 9 β 3 3x = 6 x = 6/3 x = 2 So, x = 2, y = β3 is the solution of the given equations

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.