Ex 3.1, 7 - Chapter 3 Class 8 Understanding Quadrilaterals - Part 4

Ex 3.1, 7 - Chapter 3 Class 8 Understanding Quadrilaterals - Part 5
Ex 3.1, 7 - Chapter 3 Class 8 Understanding Quadrilaterals - Part 6
Ex 3.1, 7 - Chapter 3 Class 8 Understanding Quadrilaterals - Part 7

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Ex 3.1, 7 (b) Find x + y + z + w Given, ∠ PAB = z ∠ BAD = 60° ∠ QBC = w ∠ BCD = 120° ∠ DCR = x ∠ADC = 80° ∠ ADS = y Now, ABCD has 4 sides So, it’s a quadrilateral And we know that Sum of angles of Quadrilateral = 360° ∠BAD + ∠ABC + ∠BCD + ∠ADC = 360° 60° + ∠1 + 120° + 80° = 360° 260° + ∠1 = 360° ∠1 = 360° − 260° ∠ 1 = 100° PAD is a line segment, ∠PAB + ∠BAD = 180° z + 60° = 180° z = 180° − 60° z = 120° QBA is a line segment, ∠ABC + ∠QBC = 180° ∠1 + w = 180° 100 + w = 180° w = 180° − 100° w = 80° BR is a line segment, ∠DCR + ∠BCD = 180° x + 120° = 180° x = 180° − 120° x = 60° CS is a line segment ∠ADS + ∠ADC = 180° y + 80° = 180° y = 180° − 80° y = 100° Thus, x = 60° , y = 100° , w = 80° , z = 120° ∴ x + y + z + w = 60° + 100° + 120° + 80° = 360°

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo