Question 5 (b) - Ex 3.1 - Chapter 3 Class 8 Understanding Quadrilaterals

Last updated at August 14, 2026 by

Ex 3.1, 7 - Chapter 3 Class 8 Understanding Quadrilaterals - Part 4

Ex 3.1, 7 - Chapter 3 Class 8 Understanding Quadrilaterals - Part 5
Ex 3.1, 7 - Chapter 3 Class 8 Understanding Quadrilaterals - Part 6 Ex 3.1, 7 - Chapter 3 Class 8 Understanding Quadrilaterals - Part 7

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Ex 3.1, 7 (b) Find x + y + z + w Given, ∠ PAB = z ∠ BAD = 60° ∠ QBC = w ∠ BCD = 120° ∠ DCR = x ∠ADC = 80° ∠ ADS = y Now, ABCD has 4 sides So, it’s a quadrilateral And we know that Sum of angles of Quadrilateral = 360° ∠BAD + ∠ABC + ∠BCD + ∠ADC = 360° 60° + ∠1 + 120° + 80° = 360° 260° + ∠1 = 360° ∠1 = 360° − 260° ∠ 1 = 100° PAD is a line segment, ∠PAB + ∠BAD = 180° z + 60° = 180° z = 180° − 60° z = 120° QBA is a line segment, ∠ABC + ∠QBC = 180° ∠1 + w = 180° 100 + w = 180° w = 180° − 100° w = 80° BR is a line segment, ∠DCR + ∠BCD = 180° x + 120° = 180° x = 180° − 120° x = 60° CS is a line segment ∠ADS + ∠ADC = 180° y + 80° = 180° y = 180° − 80° y = 100° Thus, x = 60° , y = 100° , w = 80° , z = 120° ∴ x + y + z + w = 60° + 100° + 120° + 80° = 360°

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