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  1. Chapter 3 Class 8 Understanding Quadrilaterals
  2. Serial order wise

Transcript

Ex 3.2, 1 Find x in the following figures. (a) Given, Three exterior angles 125°, 125° and x We know that, Sum of the exterior angles = 360° 125° + 125° + x = 360° 250° + x = 360° x = 360° − 250° x = 110° Ex 3.2, 1 Find x in the following figures. (b) Here ABC is a line So, by Linear pair ∠ 1 + ∠ B = 180° ∠ 1 + 90° = 180° ∠ 1 = 180° – 90° ∠ 1 = 90° Thus, our exterior angles are x, 90°, 60°, 90°, 70° We know that Sum of exterior angles = 360° x + 90° + 60° + 90° + 70° = 360° x + 310° = 360° x = 360° − 310° x = 50°

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.