Ex 3.2, 5 (b) - Chapter 3 Class 8 Understanding Quadrilaterals

Last updated at Dec. 16, 2024 by

Ex 3.2, 5 - Chapter 3 Class 8 Understanding Quadrilaterals - Part 2

Ex 3.2, 5 - Chapter 3 Class 8 Understanding Quadrilaterals - Part 3

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Ex 3.2, 5 (b) Can it be an interior angle of a regular polygon? Why? Given Interior angle = 22° Now, By linear pair Interior angle + Exterior angle = 180° 22° + Exterior angle = 180° Exterior angle = 180° − 22° = 158° Let number of sides = n In a regular Polygon Sum of the exterior angles = 360° 158° × n = 360° n = 360"°" /158"°" n = 2.27 Since n cannot be in decimals, 158° external angle is not possible

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo