Chapter 2 Class 9 Polynomials
Serial order wise

Question 1 (v) - Remainder Theorem - Chapter 2 Class 9 Polynomials

Last updated at April 16, 2024 by

Ex 2.3,1 - Chapter 2 Class 9 Polynomials - Part 9

Ex 2.3,1 - Chapter 2 Class 9 Polynomials - Part 10

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Question 1 Find the remainder when x3 + 3x2 + 3x + 1 is divided by (v) 5 + 2x Dividing x3 + 3x2 + 3x + 1 by 5 + 2π‘₯ Step 1: Put Divisor = 0 5 + 2x = 0 2x = –5 x = – 5/2 Step 2: Let p(x) = x3 + 3x2 + 3x + 1 Putting x = – 5/2 p((βˆ’5)/2) = ((βˆ’5)/2)^3+ 3((βˆ’5)/2)^2 + 3((βˆ’5)/2) + 1 = (βˆ’125)/8 + 3(25/4) – 15/2 + 1 = (βˆ’125)/8 + 75/4 – 15/2 + 1 = (βˆ’125 + 75(2) βˆ’ 15(4) + 1(8) )/8 = (βˆ’125 + 150 βˆ’ 60 + 8)/8 = (βˆ’27)/8 Thus, remainder = p((βˆ’5)/2) = (βˆ’27)/8

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo