Ex 2.3,1 - Chapter 2 Class 9 Polynomials - Part 5

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Ex 2.3,1 - Chapter 2 Class 9 Polynomials - Part 6

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  1. Chapter 2 Class 9 Polynomials (Term 2)
  2. Serial order wise

Transcript

Ex 2.3, 1 Find the remainder when x3 + 3x2 + 3x + 1 is divided by (iii) x Dividing x3 + 3x2 + 3x + 1 by x Step 1: Put Divisor = 0 x = 0 Step 2: Let p(x) = x3 + 3x2 + 3x + 1 Putting x = 0 p(0) = (0)3 + 3(0)2 + 3(0) + 1 = 1 Thus, remainder = p(0) = 1

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.