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Ex 2.3,2 - Find the remainder when x3 - ax2 + 6x - a is - Ex 2.3

Ex 2.3,2 - Chapter 2 Class 9 Polynomials - Part 2

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Ex 2.3, 2 Find the remainder when x3 − ax2 + 6x − a is divided by x − a. Dividing x3 − ax2 + 6x − a by x – a Step 1: Put Divisor = 0 x – a = 0 x = a Step 2: Let p(x) = x3 − ax2 + 6x − a Putting x = a p(a) = (a)3 – a(a)2 + 6(a) – a = a3 – a3 + 6a – a = 5a Thus, Remainder = p(a) = 5a = (−125)/8 + 3(25/4) – 15/2 + 1 = (−125)/8 + 75/4 – 15/2 + 1 = (−125 + 75(2) − 15(4) + 1(8) )/8 = (−125 + 150 − 60 + 8)/8 = (−27)/8 Thus, remainder = p((−5)/2) = (−27)/8

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.