![Ex 2.3,1 - Chapter 2 Class 9 Polynomials - Part 8](https://d1avenlh0i1xmr.cloudfront.net/cb303928-9d8a-4f1d-bb9c-25494ace4a85slide40.jpg)
Remainder Theorem
Last updated at April 16, 2024 by Teachoo
Question 1 Find the remainder when x3 + 3x2 + 3x + 1 is divided by (iv) x + π Dividing x3 + 3x2 + 3x + 1 by x + π Step 1: Put Divisor = 0 x + π = 0 x = – π Step 2: Let p(x) = x3 + 3x2 + 3x + 1 Putting x = – π p("−" 𝜋) = ("−" 𝜋)3 + 3("−" 𝜋)2 + 3("−" 𝜋) + 1 = – 𝜋3 + 3𝜋2 – 3𝜋 + 1 Thus, remainder = p("−" 𝜋) = – 𝜋3 + 3𝜋2 – 3𝜋 + 1