Question 17 - NCERT Exemplar - MCQ - Chapter 8 Class 10 Introduction to Trignometry

Last updated at Dec. 16, 2024 by

sin (45° + θ) – cos (45° – θ) is equal to

(A) 2 cos θ  

(B) 0 

(C) 2 sin θ  

(D) 1

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Question 17 sin (45° + θ) – cos (45° – θ) is equal to (A) 2 cos θ (B) 0 (C) 2 sin θ (D) 1 Now, sin (45° + θ) – cos (45° – θ) Using sin A = cos (90° − A) = cos (90° − [45° + θ] ) – cos (45° – θ) = cos (90° − 45° − θ) – cos (45° – θ) = cos (45° − θ) – cos (45° – θ) = 0 So, the correct answer is (B)

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