sin (45° + θ) – cos (45° – θ) is equal to
(A) 2 cos θ
(B) 0
(C) 2 sin θ
(D) 1

Get live Maths 1-on-1 Classs - Class 6 to 12
NCERT Exemplar - MCQ
Last updated at March 22, 2023 by Teachoo
Get live Maths 1-on-1 Classs - Class 6 to 12
Question 17 sin (45° + θ) – cos (45° – θ) is equal to (A) 2 cos θ (B) 0 (C) 2 sin θ (D) 1 Now, sin (45° + θ) – cos (45° – θ) Using sin A = cos (90° − A) = cos (90° − [45° + θ] ) – cos (45° – θ) = cos (90° − 45° − θ) – cos (45° – θ) = cos (45° − θ) – cos (45° – θ) = 0 So, the correct answer is (B)