## sin (45° + θ) – cos (45° – θ) is equal to

## (A) 2 cos θ

## (B) 0

## (C) 2 sin θ

## (D) 1

Last updated at Aug. 19, 2021 by Teachoo

Transcript

Question 17 sin (45° + θ) – cos (45° – θ) is equal to (A) 2 cos θ (B) 0 (C) 2 sin θ (D) 1 Now, sin (45° + θ) – cos (45° – θ) Using sin A = cos (90° − A) = cos (90° − [45° + θ] ) – cos (45° – θ) = cos (90° − 45° − θ) – cos (45° – θ) = cos (45° − θ) – cos (45° – θ) = 0 So, the correct answer is (B)

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.