Question 8 - NCERT Exemplar - MCQ - Chapter 8 Class 10 Introduction to Trignometry

Last updated at August 14, 2026 by

If cos (α + β) = 0, then sin (α – β) can be reduced to

(A) cos β   (B) cos 2β   (C) sin α   (D) sin 2α

MCQ - If cos (α + β) = 0, then sin (α - β) can be reduced to - Teachoo - NCERT Exemplar - MCQ

part 2 - Question 8 - NCERT Exemplar - MCQ - Serial order wise - Chapter 8 Class 10 Introduction to Trignometry

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Question 8 If cos (α + β) = 0, then sin (α – β) can be reduced to (A) cos β (B) cos 2β (C) sin α (D) sin 2α Given that cos (α + β) = 0 cos (α + β) = cos 90° Comparing angles α + β = 90° α = 90° − β Now, sin (α – β) = sin (90° − β − β) = sin (90° − 2β) Using cos A = sin (90° − A) = cos 2β So, the correct answer is (B)

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