Question P(x) = ćā5š„ć^2+125š„+37500 is the total profit function of a company, where x is the production of the company.
Question 1 What will be the production when the profit is maximum? (a) 37500 (b) 12.5 (c) ā12.5 (d) ā37500
Given
P(x) = ā5x2 + 125x + 37500
Differentiating w.r.t x
Pā(x) = d(ćā5š„ć^2 + 125š„ + 37500)/šš„
Pā(x) = ā5 Ć 2x + 125
Pā(x) = ā10x + 125
Putting Pā(x) = 0
ā10x + 125 = 0
ā10x = --125
x = (ā125)/(ā10)
x = 12.5
Finding Pāā(x)
Pāā(x) = d(ā10š„ + 125)/šš„
Pāā(x) = ā10
< 0
Since Pāā(š) < 0 at š„ = 12.5
ā“ š„ = 12.5 is point of maxima
Thus, P(š„) is maximum when š = 12.5
So, the correct answer is (b)
Question 2 What will be the maximum profit? (a) Rs 38,28,125 (b) Rs 38281.25 (c) Rs 39,000 (d) None
Putting x = 12.5 in P(x)
P(x) = ā5x2 + 125x + 37500
= ā5(12.5)2 + 125(12.5) + 37500
= ā5(156.25) + 1562.5 + 37500
= ā781.25 + 1562.5 + 37500
= 781.25 + 37500
= Rs 38281.25
So, the correct answer is (b)
Question 3 Check in which interval the profit is strictly increasing . (a) (12.5, ā) (b) for all real numbers (c) for all positive real numbers (d) (0, 12.5)
Profit is strictly increasing where
Pā(x) > 0
ā10x + 125 > 0
125 > 10x
10x < 125
x < 12.5
So, profit is strictly increasing for x ā (0, 12.5)
So, the correct answer is (d)
Question 4 When the production is 2 units, what will be the profit of the company? (a) 37,500 (b) 37,730 (c) 37,770 (d) None
Putting x = 2 in P(x)
P(x) = ā5x2 + 125x + 37500
= ā5(2)2 + 125(2) + 37500
= ā5(4) + 250 + 37500
= ā20 + 250 + 37500
= 230 + 37500
= Rs 37730
So, the correct answer is (b)
Question 5 What will be production of the company when the profit is Rs 38,250? (a) 15 (b) 30 (c) 2 (d) data is not sufficient to find
Putting P(x) = 38250 in formula of P(x)
P(x) = ā5x2 + 125x + 37500
38250 = ā5x2 + 125x + 37500
5x2 ā 125x ā 37500 + 38250 = 0
5x2 ā 125x + 750 = 0
Dividing both sides by 5
x2 ā 25x + 150 = 0
x2 ā 10x ā 15x + 150 = 0
x(x ā 10) ā 15(x ā 10) = 0
(x ā 10) (x ā 15) = 0
ā“ x = 10, 15
Since x = 15 is in the options
So, the correct answer is (a)
Made by
Davneet Singh
Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.
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