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Last updated at May 29, 2018 by Teachoo

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Ex 12.2, 4 A triangle and a parallelogram have the same base and the same area. If the sides of triangle are 26 cm, 28 cm and 30 cm, and the parallelogram stands on the base 28 cm, find the height of the parallelogram. Given that Area of parallelogram = Area of triangle Base Height = Area of triangle 28 Height = Area of triangle Height = 1/28 Area of triangle Finding Area of triangle Area of triangle Area of triangle = (s(s a)(s b)(s c)) Here, s is the semi-perimeter, and a, b, c are the sides of the triangle Here, a = 26 , b = 28 , c = 30 s = ( + + )/2 Area of triangle = (42(42 26)(42 28)(42 30)) cm2 = (42(16)(14)(12)) = ((14 3) (16) (14) (12)) = ((14 14) (12 3) (16) ) = ((142) (36) (16) ) = ((142) (62) (42) ) = ((14)2) ((6)2) ((4)2) = 14 6 4 = 336 cm2 Thus, Area of triangle = 336 cm2 Now, Height = 1/28 Area of triangle Height = 1/28 336 Height = 12 cm Therefore, the height of the parallelogram is 12 cm.

Ex 12.2

Ex 12.2, 1
Not in Syllabus - CBSE Exams 2021

Ex 12.2, 2 Not in Syllabus - CBSE Exams 2021

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Ex 12.2, 5 Important Not in Syllabus - CBSE Exams 2021

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.