Rahul is studying in X Standard. He is making a kite to fly it on a Sunday. Few questions came to his mind while making the kite. Give answers to his questions by looking at the figure

 

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  1. Class 10
  2. Solutions of Sample Papers for Class 10 Boards

Transcript

Question 19 Rahul is studying in X Standard. He is making a kite to fly it on a Sunday. Few questions came to his mind while making the kite. Give answers to his questions by looking at the figureQuestion 19 (i) Rahul tied the sticks at what angles to each other? (a) 30° (b) 60° (c) 90° (d) 60° At 90° Question 19 (ii) Which is the correct similarity criteria applicable for smaller triangles at the upper part of this kite? (a) RHS (b) SAS (c) SSA (d) AAS The two triangles have One Common side One angle 90° One Side Equal So, we use SAS similarity Question 19 (iii) Sides of two similar triangles are in the ratio 4 : 9. Corresponding medians of these triangles are in the ratio, (a) 2 : 3 (b) 4 : 9 (c) 81 : 16 (d) 16 : 81 If two sides are in ratio 4 : 9 The corresponding medians would be in the same ratio ∴ Required Ratio is 4 : 9 1 marks Question 19 (iv) In a triangle, if square of one side is equal to the sum of the squares of the other two sides, then the angle opposite the first side is a right angle. This theorem is called as, (a) Pythagoras theorem (b) Thales theorem (c) Converse of Thales theorem (d) Converse of Pythagoras theorem Converse of Pythagoras Theorem 1 marks Question 19 (v) What is the area of the kite, formed by two perpendicular sticks of length 6 cm and 8 cm? (a) 48 cm2 (b) 14 cm2 (c) 24 cm2 (d) 96 cm2 Given Height = 6 cm & Base = 8 cm Thus, Area of Kite = 2 × Area of Triangle = 2 × 1/2 × Base × Height = 2 × 1/2 × 8 × 6 = 8 × 6 = 48 cm2 1 marks

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.