Ex 3.6, 2 (ii) - 2 women and 5 men can together finish an embroidery

 

 

Ex 3.6, 2 (ii) - Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Part 2

Ex 3.6, 2 (ii) - Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Part 3
Ex 3.6, 2 (ii) - Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Part 4
Ex 3.6, 2 (ii) - Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Part 5 Ex 3.6, 2 (ii) - Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Part 6 Ex 3.6, 2 (ii) - Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Part 7

 

 

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Question 2 (Introduction) Formulate the following problems as a pair of equations, and hence find their solutions: (ii) 2 women & 5 men can together finish an embroidery work in 4 days, while 3 women & 6 men can finish it in 3 days. Find the time taken by 1 woman alone to finish the work, & also that taken by 1 man alone. A person completes work in 2 days Work completed in 1 day = 1/2 A person completes work in 3 days Work completed in 1 day = 1/3 A person completes work in x days Work completed in 1 day = 1/𝑥 We will use this theory in our question Question 2 Formulate the following problems as a pair of equations, and hence find their solutions: (ii) 2 women & 5 men can together finish an embroidery work in 4 days, while 3 women & 6 men can finish it in 3 days. Find the time taken by 1 woman alone to finish the work, & also that taken by 1 man alone. Let time taken by 1 woman to finish the work = x days Work finished by 1 woman in 1 day = 1/𝑥 Similarly, Let time taken by 1 man to finish the work = y days Work finished by 1 man in 1 day = 1/𝑦 Given that 2 women and 5 men complete the work in 4 days ∴ Work finished by 2 women and 5 men in 1 day = 1/4 2 × (Work finished by 1 woman in 1 day) + 5 × (Work finished by 1 man in 1 day) 2 × 1/𝑥 + 5 × 1/𝑦 = 1/4 2/𝑥 + 5/𝑦 = 1/4 Also, 3 women and 6 men complete the work in 3 days ∴ Work finished by 3 women and 6 men in 1 day = 1/3 3 × (Work finished by 1 woman in 1 day) + 6 × (Work finished by 1 man in 1 day) 3 × 1/𝑥 + 6 × 1/𝑦 = 1/3 3/𝑥 + 6/𝑦 = 1/3 Our two equations become 2/𝑥 + 5/𝑦 = 1/4 …(1) 3/𝑥 + 6/𝑦 = 1/3 …(2) So, our equations become 2u + 5v = 1/4 4(2u + 5v) = 1 8u + 20v = 1 3u + 6v = 1/3 3(3u + 6v) = 1 9u + 18v = 1 Hence, our equations are 8u + 20v = 1 …(3) 9u + 18v = 1 …(4) From (3) 8u + 20v = 1 8u = 1 – 20v u = (1 − 20𝑣)/8 Putting value of u in (4) 9u + 18v = 1 9 ((1 − 20𝑣)/8) + 18v = 1 Multiplying both sides by 8 8 × 9 ((1 − 20𝑣)/8) + 8 × 18v = 8 × 1 9(1 – 20v) + 144v = 8 9 – 180v + 144v = 8 – 180v + 144v = 8 – 9 −36v = –1 v = (−1)/(−36) v = 1/36 Putting v = 1/36 in (3) 8u + 20v = 1 8u + 20(1/36) = 1 8u + 5/9 = 1 8u = 1 – 5/9 8u = (9 − 5)/9 8u = 4/9 u = 4/(9 × 8) u = 1/18 Hence, u = ( 𝟏)/( 𝟏𝟖 ), v = 𝟏/𝟑𝟔 But we have to find x & y We know that u = 𝟏/𝒙 1/18 = 1/𝑥 x = 18 v = 𝟏/𝒚 1/36 = 1/𝑦 y = 36 So, x = 18 , y = 36 is the solution of the given equation ∴ Time taken by one woman to finish the work alone = x = 18 days & Time taken by one man to finish the work alone = y = 36 days

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.