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Example 6 - In figure, AB || CD and CD || EF. Also EA ⊥ AB - Parallel lines and traversal - Problems

Example 6 - Chapter 6 Class 9 Lines and Angles - Part 2


Transcript

Example 6 In figure, AB || CD and CD || EF. Also EA ⊥ AB. If ∠ BEF = 55°, find the values of x, y and z. Given AB || CD and BE is the transversal So, x = y Also, CD || EF and BE is transversal So, y + 55° = 180° y = 180° – 55° y = 125° From (1) x = y x = 125° Also, AB || EF and AE is transversal So, ∠ BAE + FEA = 180° 90° + (z + 55°) = 180° 55° + 90° + z = 180° 145° + z = 180° z = 180° – 145° z = 35°

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.