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Ex 6.3, 1 - In figure, sides QP & RQ of ΔPQR are produced - Triangle - Problems

Ex 6.3, 1 - Chapter 6 Class 9 Lines and Angles - Part 2

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Ex 6.3, 1 In the given figure, sides QP and RQ of ΔPQR are produced to points S and T respectively. If ∠SPR = 135° and ∠PQT = 110°, find ∠PRQ. Since TR is a line ∠ PQT + ∠ PQR = 180° 110° + ∠ PQR = 180° ∠ PQR = 180° – 110° ∠ PQR = 70° Since QS is a line ∠ SPR + ∠ QPR = 180° 135° + ∠ QPR = 180° ∠ QPR = 180° – 135° ∠ QPR = 45° In Δ PQR, ∠ QPR + ∠ PQR + ∠ PRQ = 180° 45° + 70° + ∠ PRQ = 180° 115° + ∠ PRQ = 180° ∠ PRQ = 180° – 115° ∠ PRQ = 65°

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.