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Ex 6.3, 3 - In figure, if AB || DE, ∠BAC = 35° & ∠CDE = 53° - Triangle - Problems

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Ex6.3, 3 In the given figure, if AB || DE, BAC = 35 and CDE = 53 , find DCE. Since AB || DE and AE is a transversal. BAC = CED 35 = CED CED = 35 In CDE, CDE + CED + DCE = 180 53 + 35 + DCE = 180 88 + DCE = 180 DCE = 180 88 DCE = 92

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.