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Example 4 - Chapter 6 Class 9 Lines and Angles (Term 1)

Last updated at Dec. 8, 2016 by

Example 4 - In figure, if PQ || RS, ∠MXQ = 135° & ∠MYR = 40° - Parallel lines and traversal - Problems

Example 4 - Chapter 6 Class 9 Lines and Angles - Part 2

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Example 4 In figure, if PQ || RS, MXQ = 135 and MYR = 40 , find XMY. Let AB || PQ, drawn through point M Since PQ || RS, AB || RS Since AB || PQ and MX is the transversal XMB + QXM = 180 XMB + 135 = 180 XMB = 180 135 XMB = 45 Similarly, Since AB || RS and MY is the transversal BMY = RYM BMY = 40 Now, XMY = XMB + MBY XMY = 45 + 40 XMY = 85

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