1. Chapter 6 Class 9 Lines and Angles
  2. Serial order wise
  3. Examples

Example 4 - Chapter 6 Class 9 Lines and Angles

Last updated at Dec. 8, 2016 by

Example 4 - In figure, if PQ || RS, ∠MXQ = 135° & ∠MYR = 40° - Parallel lines and traversal - Problems

  1. Chapter 6 Class 9 Lines and Angles
  2. Serial order wise
    3. Examples
    Theorems  →
Ask Download

Transcript

Example 4 In figure, if PQ || RS, MXQ = 135 and MYR = 40 , find XMY. Let AB || PQ, drawn through point M Since PQ || RS, AB || RS Since AB || PQ and MX is the transversal XMB + QXM = 180 XMB + 135 = 180 XMB = 180 135 XMB = 45 Similarly, Since AB || RS and MY is the transversal BMY = RYM BMY = 40 Now, XMY = XMB + MBY XMY = 45 + 40 XMY = 85

Chapter 6 Class 9 Lines and Angles
Serial order wise

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.