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Last updated at May 23, 2019 by Teachoo

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Page 109 Q1 A bus starting from rest moves with a uniform acceleration of 0.1 m s-2 for 2 minutes. Find (a) the speed acquired, (b) the distance travelled. Since bus starts from rest, Initial velocity = u = 0 m/s Acceleration = a = 0.1 m/s2 Time = t = 2 minutes = 2 × 60 seconds = 120 s Speed Acquired Speed acquired will be the final velocity Speed acquired = Final velocity = v Since we know u, a and t We use first equation of motion, v = u + at = 0 + 0.1 × 120 = 12 m/s Thus, Speed acquired is 12 m/s (b) Distance Travelled We find Distance travelled by 2nd equation of motion s = ut + 1/2 at2 Putting values s = 0 × 120 + 1/2 × 0.1 × (120)2 s = 0 + 1/2 × 1/10 × 14400 s = 720 m Thus, Distance travelled is 720 m

Questions from Inside the chapter

Question 1 Page 100

Question 2 Page 100

Question 3 Page 100

Difference between speed and velocity (Question 1 Page 102)

Question 2 Page 102

Question 3 Page 102

Question 4 Page 102

Question 5 Page 102

Question 1 Page 103

Question 2 Page 103

Question 3 Page 103

Question 1 Page 107

Question 2 Page 107

Question 3 Page 107

Question 4 Page 107

Question 1 Page 109 You are here

Question 2 Page 110

Question 3 Page 110

Question 4 Page 110

Question 5 Page 110

Class 9

Chapter 8 Class 9 - Motion

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.