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Last updated at May 23, 2019 by Teachoo

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Page 103 Q3 A train starting from a railway station & moving with uniform acceleration attains a speed 40 km h–1 in 10 minutes. Find its acceleration. Since the train starts from rest, Initial velocity = u = 0 km/h Final velocity = v = 40 km/h Time taken = t = 10 minutes = 10 × 60 seconds = 600 seconds Since time is in seconds, we’ll convert the initial and final velocity from km/h to m/s. Conversion from km/h to m/s 1 km = 1000 m 1 hour = 60 minutes = 3600 s ∴ (1 𝑘𝑚)/ℎ = (1000 𝑚)/(3600 𝑠) ∴ 1 km/h = 5/18 m/s Initial velocity = u = 0 km/h = 0 × 5/18 m/s = 0 m/s Final velocity = v = 40 km/h = 40 × 5/18 m/s = 200/18 m/s Acceleration = (𝐹𝑖𝑛𝑎𝑙 𝑣𝑒𝑙𝑜𝑐𝑖𝑡𝑦 − 𝐼𝑛𝑖𝑡𝑖𝑎𝑙 𝑉𝑒𝑙𝑜𝑐𝑖𝑡𝑦)/𝑇𝑖𝑚𝑒 = (𝑣 − 𝑢)/𝑡 = (200/18 − 0)/600 = (200/18)/600 = 200/(18 × 600) = 1/(18 × 3) = 1/54 = 0.0185 m/s2

Questions from Inside the chapter

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Question 4 Page 102

Question 5 Page 102

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Question 3 Page 103 You are here

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Question 1 Page 109

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Question 5 Page 110

Class 9

Chapter 8 Class 9 - Motion

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.