Check sibling questions


Transcript

Ex 5.7, 10 Find the second order derivatives of the function 〖 sin〗⁡〖 (log⁡〖𝑥)〗 〗 Let y = 〖 sin〗⁡〖 (log⁡〖𝑥)〗 〗 Differentiating 𝑤.𝑟.𝑡.𝑥 . 𝑑𝑦/𝑑𝑥 = (𝑑(〖 sin〗⁡〖 (log⁡〖𝑥)〗 〗))/𝑑𝑥 𝑑𝑦/𝑑𝑥 = cos⁡(log⁡𝑥) . (𝑑(log⁡〖𝑥)〗)/𝑑𝑥 𝑑𝑦/𝑑𝑥 = cos⁡(log⁡𝑥) . 1/𝑥 𝑑𝑦/𝑑𝑥 = (cos⁡(log⁡𝑥))/𝑥 Again Differentiating 𝑤.𝑟.𝑡.𝑥 𝑑/𝑑𝑥 (𝑑𝑦/𝑑𝑥) = 𝑑/𝑑𝑥 ((cos⁡(log⁡𝑥))/𝑥) (𝑑^2 𝑦)/(𝑑𝑥^2 ) = 𝑑/𝑑𝑥 ((cos⁡(log⁡𝑥))/𝑥) (𝑑^2 𝑦)/(𝑑𝑥^2 ) = ((𝑑(cos⁡(log⁡𝑥)))/𝑑𝑥 . 𝑥 − (𝑑 (𝑥))/𝑑𝑥 . cos⁡(log⁡𝑥))/𝑥^2 (𝑑^2 𝑦)/(𝑑𝑥^2 ) = (−〖sin 〗⁡(log⁡𝑥 ) . 𝑑(log⁡𝑥 )/𝑑𝑥 . 𝑥 − 1 . cos⁡(log⁡𝑥))/𝑥^2 Using Quotient Rule As, (𝑢/𝑣)^′= (𝑢’𝑣 − 𝑣’𝑢)/𝑣^2 where v = cos (log x) & v = x (𝑑^2 𝑦)/(𝑑𝑥^2 ) = (−〖sin 〗⁡(log⁡𝑥 ) . 1/𝑥 . 𝑥 − cos ⁡(log⁡𝑥))/𝑥^2 (𝑑^2 𝑦)/(𝑑𝑥^2 ) = (−〖sin 〗⁡(log⁡𝑥 ) − cos⁡(log⁡𝑥))/𝑥^2 (𝒅^𝟐 𝒚)/(𝒅𝒙^𝟐 ) = (− [〖𝒔𝒊𝒏 〗⁡(𝒍𝒐𝒈⁡𝒙 ) + 𝒄𝒐𝒔⁡(𝒍𝒐𝒈⁡𝒙)])/𝒙^𝟐

  1. Chapter 5 Class 12 Continuity and Differentiability
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo