Example 7 - Chapter 1 Class 11 Sets
Last updated at Dec. 13, 2024 by Teachoo
Last updated at Dec. 13, 2024 by Teachoo
Example 7 Find the pairs of equal sets, if any, give reasons: A = {0}, B = {x : x > 15 and x < 5}, C = {x : x – 5 = 0 }, D = {x: x2 = 25}, E = {x : x is an integral positive root of the equation x2 – 2x –15 = 0}. Let’s write all the sets in roster form A = {0} A = {0} B = {x : x > 15 and x < 5}, No number can be greater than 15 and less than 5 simultaneously. B = {} = Φ C = {x : x – 5 = 0} x – 5 = 0 , x = 5 . So, C = {5} D = {x: x2 = 25} x2 = 25 x = ±5 So, D = { +5, −5} E = {x : x is an integral positive root of the equation x2 – 2x –15 = 0}. x2 – 2x −15 =0 x2 – 5x + 3x – 15 =0 x(x – 5) + 3 (x – 5) = 0 (x − 5) (x + 3) = 0 x = 5 , −3 Since x is positive E = {5} Thus, A = {0} B = { } C = {5} D = { +5,-5} E = { 5} Therefore only C = E, as there elements are exactly the same
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo