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Question 1 Solve the equation given in Example 3 (2x2 5x + 3 = 0) by the method of completing the square. 2x2 5x + 3 = 0 Dividing by 2 (2 2 5 + 3)/2=0/2 2 2/2 5 /2+3/2=0 x2 5 /2+3/2=0 We know that (a b)2 = a2 2ab + b2 Here, a = x & 2ab = ( 5 )/2 2xb = ( 5 )/2 2b = ( 5)/2 b = ( 5)/(2( 2)) b = 5/4 Now, in our equation x2 5 /2+3/2=0 Adding and subtracting (5/4)^2 x2 5 /2+3/2+(5/4)^2 (5/4)^2=0 x2 +(5/4)^2 5 /2+3/2 (5/4)^2=0 ( 5/4)^2 +3/2 (5/4)^2=0 ( 5/4)^2 +3/2 25/16=0 ( 5/4)^2=25/16 3/2 ( 5/4)^2=(25 3(8))/16 ( 5/4)^2=(25 24)/16 ( 5/4)^2=1/16 ( 5/4)^2=(1/4)^2 Cancelling square 5/4 = 1/4 5/4 = 1/4 Solving So, the roots of the equation are x = 3/2 & x = 1

  1. Chapter 4 Class 10 Quadratic Equations
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo