Ex 6.1, 2 (ii) - Chapter 6 Class 8 Cubes and Cube Roots
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Ex 6.1, 2 Find the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube. (ii) 256 We see that 256 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 Since 2 does not occur in triplets, ∴ 256 is not a perfect cube. So, we multiply by 2 to make triplet So, our number becomes 256 × 2 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 Now, it becomes a perfect cube. So, we multiply 256 by 2 to make it a perfect cube
Ex 6.1
Ex 6.1, 1 (ii)
Ex 6.1, 1 (iii) Important
Ex 6.1, 1 (iv)
Ex 6.1, 1 (v) Important
Ex 6.1, 2 (i)
Ex 6.1, 2 (ii) Important You are here
Ex 6.1, 2 (iii)
Ex 6.1, 2 (iv) Important
Ex 6.1, 2 (v)
Ex 6.1, 3 (i) Important
Ex 6.1, 3 (ii)
Ex 6.1, 3 (iii)
Ex 6.1, 3 (iv) Important
Ex 6.1, 3 (v)
Ex 6.1, 4 Important
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo