1. Chapter 7 Class 10 Coordinate Geometry
  2. Serial order wise
  3. NCERT Exemplar - MCQ
Check sibling questions

Question 10 - NCERT Exemplar - MCQ - Chapter 7 Class 10 Coordinate Geometry

Last updated at Dec. 16, 2024 by Teachoo

The area of a triangle with vertices A (3, 0), B (7, 0) and C (8, 4) is

(A) 14   (B) 28   (C) 8   (D) 6

 

Transcript

Question 10 The area of a triangle with vertices A (3, 0), B (7, 0) and C (8, 4) is (A) 14 (B) 28 (C) 8 (D) 6 Since points are A (3, 0), B (7, 0) and C (8, 4) Here x1 = 3 , y1 = 0 x2 = 7 , y2 = 0 x3 = 8 , y3 = 4 Now, Area of triangle ABC = 1/2 [ x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2) ] = 1/2 [ 3(0 – 4) + 7(4 – 0) + 8(0 − 0) ] = 1/2 [ 3 × −4 + 7 × 4 + 8 × 0 ] = 1/2 [ −12 + 28 + 0 ] = 1/2 × 16 = 8 square units So, the correct answer is (C)
  1. Chapter 7 Class 10 Coordinate Geometry
  2. Serial order wise

    3. NCERT Exemplar - MCQ

    Past Year MCQ →
Past Year MCQ →
Chapter 7 Class 10 Coordinate Geometry
Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo