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Transcript

Substituting x in (2) โˆš3 ๐‘ฅโˆ’โˆš8 ๐‘ฆ=0 โˆš3 ((โˆ’โˆš3 ๐‘ฆ)/โˆš2)โˆ’โˆš8 ๐‘ฆ = 0 (โˆš3 ร— (โˆ’โˆš3 ๐‘ฆ))/โˆš2โˆ’โˆš8 ๐‘ฆ=0 (โˆ’3๐‘ฆ)/โˆš2โˆ’โˆš8 ๐‘ฆ=0 โ€“3y โ€“ โˆš8 ๐‘ฆ ร— โˆš2= โˆš2 ร— 0 โ€“3y โ€“ โˆš(8 ร— 2) ๐‘ฆ=0 โ€“3y โ€“ โˆš16 ๐‘ฆ=0 โ€“3y โ€“ โˆš(4 ร— 4) ๐‘ฆ=0 โ€“3y โ€“ โˆš42 ๐‘ฆ=0 โ€“3y โ€“ 4y = 0 โ€“7y = 0 y = 0/(โˆ’7) y = 0 Putting the value of y in (1) โˆš2 ๐‘ฅ+โˆš3 ๐‘ฆ=0 โˆš2 ๐‘ฅ+โˆš3 ร— 0=0 โˆš2 ๐‘ฅ+0=0 โˆš2 ๐‘ฅ=0 x = 0/โˆš2 x = 0 Hence, x = 0, y = 0

  1. Chapter 3 Class 10 Pair of Linear Equations in Two Variables
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo