1. Chapter 7 Class 9 Triangles
  2. Serial order wise
  3. Angle opposite to longer side
Check sibling questions

Question 5 - Angle opposite to longer side - Chapter 7 Class 9 Triangles

Last updated at Dec. 13, 2024 by Teachoo

Transcript

Ex7.4, 5 In the given figure, PR > PQ and PS bisects ∠QPR. Prove that ∠PSR >∠PSQ. Given PR > PQ, ∴ ∠PQR > ∠PRQ PS is the bisector of ∠QPR. ∴ ∠QPS = ∠RPS Let ∠QPS = ∠RPS = x In Δ PQS, ∠PSR is the exterior angle ∠PSR = ∠PQR + x Now, ∠ PQR > ∠ PRQ Adding x both sides ∠PQR + x > ∠PRQ + x ∠PSR > ∠PSQ Hence proved
  1. Chapter 7 Class 9 Triangles
  2. Serial order wise

    3. Angle opposite to longer side

    Important Triangle Questions →
Important Triangle Questions →
Chapter 7 Class 9 Triangles
Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo