1. Chapter 7 Class 9 Triangles
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  3. Angle opposite to longer side
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Question 3 - Angle opposite to longer side - Chapter 7 Class 9 Triangles

Last updated at Dec. 13, 2024 by Teachoo

Transcript

Ex7.4, 3 In the given figure, ∠B < ∠A and ∠C < ∠D. Show that AD < BC. In ΔAOB, ∠B < ∠A ⇒ AO < BO (Side opposite to the greater angle is longer) In ΔCOD, ∠C < ∠D OD < OC (Side opposite to the greater angle is longer) Adding equations (1) and (2), AO + OD < BO + OC AD < BC Hence proved
  1. Chapter 7 Class 9 Triangles
  2. Serial order wise

    3. Angle opposite to longer side

    Important Triangle Questions →
Important Triangle Questions →
Chapter 7 Class 9 Triangles
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo