Last updated at Dec. 13, 2024 by Teachoo
Ex 7.3,5 ABC is an isosceles triangle with AB = AC . Draw AP ⊥ BC to show that ∠𝐵 = ∠𝐶. Given: Since ∆ ABC is isosceles AB = AC Given AP ⊥ BC , So, ∠APB = ∠APC = 90∘ To prove: ∠ B = ∠ C Proof: In ∆ABP and ∆ACP ∠APB = ∠APC = 90∘ AB = AC AP = AP ∆ ABP ≅ ∆ ACP So, ∠B = ∠C Hence proved
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo