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Jayanti throws a pair of dice and records the product of the numbers appearing on the dice. Pihu throws 1 dice and records the squares the number that appears on it. Who has the better chance of getting the number 36? Justify?


Transcript

Question 25 (OR 1st question) Jayanti throws a pair of dice and records the product of the numbers appearing on the dice. Pihu throws 1 dice and records the squares the number that appears on it. Who has the better chance of getting the number 36? Justify? For Jayanti She throws the dice twice Total outcomes = 36 Number of outcomes where product is 36 = 1 So, Probability Jayanti gets 36 = 𝟏/𝟑𝟔 For Pihu She throws the dice once Possible outcomes = 1, 2, 3, 4, 5, 6 Square of outcomes = 12, 22, 32, 42, 52, 62 = 1, 4, 9, 16, 25, 36 Therefore, Total outcomes = 6 Number of outcomes where she gets 36 = 1 So, Probability Pihu gets 36 = 𝟏/𝟔 Since P(Pihu) > P(Jayanti) Pihu has a better chance of getting 36

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo