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Question 21 - CBSE Class 10 Sample Paper for 2020 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards

Last updated at Dec. 16, 2024 by Teachoo

Find the number of natural numbers between 102 and 998 which are divisible by 2 and 5 both

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Question 21 Find the number of natural numbers between 102 and 998 which are divisible by 2 and 5 both Numbers b/w 102 and 998 which are divisible by 2 and 5 both = Numbers b/w 102 and 998 which are divisible by 10 = 110, 120, 130, 140, …… 990 This is an AP, where First Term = a = 110 Common difference = d = 120 – 110 = 10 nth term = 990 We need to find n We know that an = a + (n – 1)d Putting values 990 = 110 + (n – 1) × 10 990 – 110 = (n – 1) × 10 880 = (n – 1) × 10 880/10 = (n – 1) 88 = n – 1 n – 1 = 88 n = 88 + 1 n = 89 So, there are 89 natural numbers
  1. Class 10
  2. Solutions of Sample Papers for Class 10 Boards

    3. CBSE Class 10 Sample Paper for 2020 Boards - Maths Standard

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo